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Q.

5 mol of A and 6 mol of Z are mixed with sufficient amount of C to produce final product F. How many maximum moles of F can be produced as per the given sequence of reaction?A+2Z→B;B+C→Z+F

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a

3

b

2

c

4

d

5

answer is A.

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Detailed Solution

Net reaction is:A+2Z+C→Z+FAs per the given information Z is the limitary reactant..'. The no. of moles of F produced  =12×6=3
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