$$1$$ mol. $$N2$$ and $$3$$ mol $$H2$$ are placed in a closed container at a pressure of $$4$$ atm. The pressure falls to $$3$$ atm at the same temperature when the following equilibrium is attained. $$N2(g)+3H2(g)$$⇌$$2NH3(g)$$ . The equilibrium constant Kp for dissociation of $$NH3$$ is :

Question

$$1$$  mol. $$N2$$      and $$3$$ mol $$H2$$      are placed in a  closed container at a pressure of $$4$$ atm.   The pressure falls to $$3$$ atm at the same temperature when the following  equilibrium is attained.  $$N2(g)+3H2(g)$$⇌$$2NH3(g)$$     .  The equilibrium  constant Kp for dissociation of $$NH3$$      is :

Infinity Learn · Accepted Answer

$$2NH3(g)$$⇌$$N2(g)+3H2(g)$$       At equilibrium          $$2x$$                    $$1-x$$            $$3-$$ $$3x$$                                     $$1-x+3-3x+2x=$$ $$3$$ (given)                                      $$4$$ – $$2x$$        $$=$$    $$3$$                                             X          $$=$$   $$0.5$$                                    $$kp=$$[$$N2$$][$$H2$$]$$3$$[$$NH3$$]$$2=$$[$$0.5$$][$$1.5$$]$$3$$[$$0.5$$]$$2=$$[$$1.5$$]$$3$$[$$0.5$$]atm−$$2$$

1 mol. N2 and 3 mol H2 are placed in a closed container at a pressure of 4 atm. The pressure falls to 3 atm at the same temperature when the following equilibrium is attained. N2(g)+3H2(g)⇌2NH3(g) . The equilibrium constant Kp for dissociation of NH3 is :

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