1.0 molal aqueous solution of an electrolyte X3Y2 is 25% ionized. The boiling point of the solution is (Kb for H2O=0.52 K kg/mol)

x3y2⇌3x2++2y3− for complete ionization. 1−α           nα             mαi=1+(m+n−1)αi=1+(2+3−1)×0.25=1+1=2ΔTb=i×kb×m=2×0.52×1=1.04B.P. of solution (Tb)=ΔTb+Tbo=1.04+373=374.04 K