A 3.5 molal aqueous solution of methyl alcohol (CH3OH) is supplied. What is the mole fraction of methyl alcohol in the solution?

Moles of (solute) CH3OH1 kg of H2O=3.5 mole1 kgThus, nCH3OH=3.5n(H2O)=100018=55.56∴ Total moles = 3.5 + 55.56 = 59.06 mol∴ xCH3OH=Moles of CH3OHTotal moles=3.559.05=0.059