Q.

The molal boiling point constant for water is 0.5 13 K m-1. When 0.1 mole of sugar is dissolved in 200.0 g of water, the solution boils under a pressure 1.0 atm at

Moderate

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100.513°C

100.0513°C

100.256°C

101.025°C

answer is 3.

(Detailed Solution Below)

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Detailed Solution

∆Tb=Kb.m=0.513×0.1200/1000=0.256°C ⇒Tb=100+0.256=100.256°C

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