First slide

Theory of dilute solutions

Question

The molal boiling point constant for water is 0.5 13 K m^-1. When 0.1 mole of sugar is dissolved in 200.0 g of water, the solution boils under a pressure 1.0 atm at

Moderate

A

100.513 $°$ C
B

100.0513 $°$ C
C

100.256 $°$ C
D

101.025 $°$ C

Solution

$∆ T_{b} = K_{b} . m = 0.513 \times \frac{0.1}{200 / 1000} = 0.256 ° C \Rightarrow T_{b} = 100 + 0.256 = 100.256 ° C$

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