Q.
The molal freezing point constant of water is 1.86 K m-1. If 342 g of cane sugar (C12H22O11) is dissolved in 1000 g of water, the solution will freeze at – X0 C, the value of X is
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
answer is 1.86.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
∆Tf=1000×Kf×WMw =1000×1.86×342100×342=1.86 ∴ Tf=0-1.86=-1.86° C
Watch 3-min video & get full concept clarity