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Q.

The molal freezing point constant of water is 1.86 K m-1. If 342 g of cane sugar (C12H22O11) is dissolved in 1000 g of water, the solution will freeze at – X0 C, the value of X is

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answer is 1.86.

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Detailed Solution

∆Tf=1000×Kf×WMw          =1000×1.86×342100×342=1.86 ∴ Tf=0-1.86=-1.86° C
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