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Molality of 110 grams of aqueous solution containing 10 grams of caustic soda is
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a
5 m
b
7.2 m
c
5.55 m
d
4.2 m
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Correct option is A
Wsolute=10 g; GMW of solute=40 g; Wsolution=110 g; Wsolvent=110-10g; m=2040×1000100=5 mTalk to our academic expert!
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Similar Questions
Match the items of Column I with Column II.
| Column I (Concentrations term) | Column II (Factor on concentration term depends) | ||
| A. | Molarity | p. | Dependent upon temperature |
| B. | Molality | q. | Not depend upon volume |
| C. | Mass per cent | r. | Depend upon volume of solution |
| D. | Volume per cent | s. | Depend upon moles of solute |
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