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Q.

Molality of a solution is 1m. If the density of the solution is 0.8g/cc, the molarity of the solution will be (molar mass of solute = 80g)

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Detailed Solution

Molality of the solution = 1mNumber moles of solute = 1Weight of solute =  1 x 80g = 80gWeight of solvent = 1000gWeight solution =   Wsolvent+Wsolute                                 =  (1000+80)gVolume of solution = wsolutiondsolution Volume of solution   = 10800.8cc                                         M = nsolute×1000Vsolution   = 1×100010800.8   = 1×8001080   = 0.74M
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