The molality of a sulfuric acid solution is 0.2. Calculate the total weight of the solution having 1000 gram of solvent. (Assuming density of water is 1 gram per m mL)

Molality (m) = number of moles of solute/weight of solvent in kgNumber of moles of solute = molality×weight of solvent in kg=0.2×1=0.2Mass of H2SO4=0.2×98=19.6gTotal mass of solution = mass of solute + mass of solvent                                               =19.6 + 1000 = 1019.6 (Because density of water is 1 gram per mL , therefore  of water = 1000 gram)