Molar conductance of 0.1 M acetic acid is 7 ohm−1 cm2 mol−1. If the molar conductance of acetic acid at infinite dilution is 380.8 ohm−1 cm2 mol−1, the value of dissociation constant will be:

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226×10−5 mol dm−3

1.66×10−3 mol dm−1

1.66×10−2 mol dm−3

3.38×10−5 mol dm−3

answer is D.

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Detailed Solution

Ka=Cα2=0.1×(7380.8)2=3.38×10−5

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