Q.
Molar conductance of 0.2 M strong electrolyte AB is 180 mho cm2mole-1. Specific conductivity of the solution at the same temperature would be------- mho m-1
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a
3.6×10-4
b
3.6×10-3
c
3.6
d
3.6×10-2
answer is C.
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Detailed Solution
∧mmho cm2mole-1=Kmho cm-1×1000Mmole/lit K=∧m×M1000=180×0.21000=3.6×10-2mho cm-1; 100 mho m-1=1 mho cm-1 'x' mho m-1=3.6×10-2mho cm-1 'x'=3.6 ;
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