Molar conductance of 0.2 M strong electrolyte AB is 180 mho cm2mole-1. Specific conductivity of the solution at the same temperature would be------- mho m-1

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3.6×10-4

3.6×10-3

3.6

3.6×10-2

answer is C.

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Detailed Solution

∧mmho cm2mole-1=Kmho cm-1×1000Mmole/lit K=∧m×M1000=180×0.21000=3.6×10-2mho cm-1; 100 mho m-1=1 mho cm-1 'x' mho m-1=3.6×10-2mho cm-1 'x'=3.6 ;

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