First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

Molar conductance of 2 M strong electrolyte AB is $' X' mho {cm}^{2} {mole}^{- 1}$ . Specific conductivity of the solution at the same temperature is 0.09 mho cm^-1. Value of ‘X’ is

Easy

A

45
B

450
C

0.045
D

0.45

Solution

$\land_{m} (mho {cm}^{2} {mole}^{- 1}) = 0.09 (mho {cm}^{- 1}) \times \frac{1000}{M (mole / lit)}; \land_{m} (mho {cm}^{2} {mole}^{- 1}) = 0.09 (mho {cm}^{- 1}) \times \frac{1000}{2 (mole / lit)}; \land_{m} (mho {cm}^{2} {mole}^{- 1}) = 45;$

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