First slide

Applications of Kohlraush law

Question

Molar conductance of 0.1 M weak mono basic acid(HA) is 36 $mho . {cm}^{2} . {mole}^{- 1}$ . At the same temperature, molar conductance of HA at infinite dilution is 360 $mho . {cm}^{2} . {mole}^{- 1}$ . $p^{H}$ of HA will be

Easy

Solution

According to Kohlraush law
$\begin{array}{l} α = \frac{Λ_{c}}{Λ_{\infty}} \\ α = \frac{36}{360} = 10^{- 1} \\ [H^{+}] = Cα \\ [H^{+}] = 10^{- 1} \times 10^{- 1} = 10^{- 2} M \\ p^{H} = 2 \end{array}$

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