Molar conductivities Λm∘ at infinite dilution of NaCl, HCI and CH3COONa are 126.4,425.9 and 91.0 S cm2mol-1 respectively. Λm∘ for CH3COOH will be

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

425.5 S cm2mol−1

180.5 S cm2 mol−1

290.85 S cm2 mol−1

390.5 S cm2 mol−1

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

CH3COONa+HCl⟶NaCl+CH3COOHΛmCH3COOH∘=ΛmCH3COONa∘+Λm(HCl)∘−Λm(NaCl)0ΛmCH3COOH=(91.0+425.9−126.4)Scm2mol−1ΛmCH3COOH=390.5Scm2mol−1

Watch 3-min video & get full concept clarity