First slide
Kohlraush law
Question

Molar conductivities  Λm at infinite dilution of NaCl, HCI and CH3COONa are 126.4,425.9 and 91.0 S cm2mol-1 respectively. Λm for CH3COOH will be

Easy
Solution

CH3COONa+HClNaCl+CH3COOH
ΛmCH3COOH=ΛmCH3COONa+Λm(HCl)Λm(NaCl)0ΛmCH3COOH=(91.0+425.9126.4)Scm2mol1ΛmCH3COOH=390.5Scm2mol1

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