The molar conductivity of a 0.5 mol/dm3 solution AgNO3 with electrolytic conductivity of 5.76×10-3 S cm at 298 K is
Λm=κ×1000 Molarity (M)=5.76×10-3Scm-1×10000.5 mol cm-3=11.52Scm2 mol-1