First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

Molar conductivity of a solution of an electrolyte AB₃ is 150 scm²mol^-1. If it ionises as ${AB}_{3} ⟶ A^{3 +} + 3 B^{-},$ its equivalent conductivity will be :

Easy

A

150 (in S cm²eq^-1)
B

75 (in S cm²eq^-1)
C

50 (in S cm²eq^-1)
D

80 (in S cm²eq^-1)

Solution

The relation between Molar and equivalent conductivities ( $λ_{eq} = \frac{1000 \times K}{N}; λ_{μ} = \frac{1000 \times K}{M}$ )
$\frac{λ_{eq}}{λ_{μ}} = \frac{1}{n} λ_{eq} = \frac{λ_{μ}}{n}$
$\land_{eq} = \frac{150}{3} = 50 S {cm}^{2} {eq}^{- 1}$

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