Molar conductivity of a solution of an electrolyte AB3 is 150 scm2mol-1. If it ionises as AB3⟶A3++3B−, its equivalent conductivity will be :

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150 (in S cm2eq-1)

75 (in S cm2eq-1)

50 (in S cm2eq-1)

80 (in S cm2eq-1)

answer is C.

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Detailed Solution

The relation between Molar and equivalent conductivities (λeq=1000×KN ; λμ=1000×KM)λeqλμ=1n λeq =λμn∧eq=1503=50Scm2eq−1

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