Molar mass of a gas is 4 grams. At certain temperature, kinetic energy per mole of the gas is 0.2×1011 ergs. At the same temperature, RMS velocity of the gas would be

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106 cm/s

105 cm/s

103 cm/s

104 cm/s

answer is B.

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Detailed Solution

K.E/mole = 32RT2 ×K.E/mole = 3 RTRMS velocity, C = 3RTMRMS velocity, C=2×K.E/moleMRMS velocity, C = 2×2×10104RMS velocity, C = 105cm/s

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