Molar mass of a gas is 16 grams. At certain temperature, R.M.S velocity of the gas is 104 cm/sec. At the same temperature, K.E/mole of the gas (in joules) would be

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8×102

4×108

4×103

answer is A.

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Detailed Solution

K.E/mole = 32RT2 ×K.E/mole = 3 RTRMS velocity, C = 3RTMRMS velocity, C=2×K.E/moleM 104 cm/s =2×K.E/mole16 ; K.E/mole = 8×108 ergs ; K.E/mole = 80 joules ;

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