Molarity of a solution of density 0.4 g/ml is 1 M. Molality of the same solution under similar conditions will be (Molar mass of solute - 100 g)
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a
1.66 m
b
5 m
c
3.33 m
d
2.5 m
answer is C.
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Detailed Solution
Molarity of the solution = 1MNumber of moles of solute = 1 Volume of the solution = 1000 mlDensity of the solution = 0.4 g/mlWeight of the solution = V x d = 400 gWeight of solute = Wsolution-Wsolute = (400 - 100) g = 300 gmolality (m) = nsolute×1000Wsolvent =1×1000300=3.33 m ;