Q.

Molarity of a solution of density 0.4 g/ml is 1 M. Molality of the same solution under similar conditions will be (Molar mass of solute - 100 g)

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a

1.66 m

b

5 m

c

3.33 m

d

2.5 m

answer is C.

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Detailed Solution

Molarity of the solution = 1MNumber of moles of solute = 1 Volume of the solution = 1000 mlDensity of the solution = 0.4 g/mlWeight of the solution = V x d = 400 gWeight of solute = Wsolution-Wsolute                          = (400 - 100) g                          = 300 gmolality (m) = nsolute×1000Wsolvent                   =1×1000300=3.33 m ;
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