Molarity of a solution of density 0.9 g/ml is 1 M. Molality of the same solution under similar conditions will be (Molar mass of solute - 150 g)
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
1.5 m
b
2 m
c
1.33 m
d
2.5 m
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Molarity of the solution = 1MNumber of moles of solute = 1Volume of the solution = 1000 mlDensity of the solution = 0.9 g/mlWeight of the solution = V x d = 900 gWeight of solute = Wsolution-Wsolute = (900 - 150) g = 750 gmolality (m) = nsolute×1000Wsolvent =1×1000750=1.33 m