Q.
Molarity of a solution of density 0.6 g/ml is 1 M. Molality of the same solution under similar conditions will be (Molar mass of solute - 150 g)
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answer is 4.
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Detailed Solution
Molarity of the solution = 1 MNumber of moles of solute = 1Volume of the solution = 1000 mlDensity of the solution = 0.6 g/mlWeight of the solution = V x d = 600 gWeight of solute = Wsolution-Wsolute = (600 - 150) g = 450 gmolality (m) = nsolute×1000Wsolvent =1.5×1000450=3.33 m
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