Q.

Molarity of a solution of density 0.6 g/ml is 1 M. Molality of the same solution under similar conditions will be (Molar mass of solute - 150 g)

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answer is 4.

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Detailed Solution

Molarity of the solution = 1 MNumber of moles of solute = 1Volume of the solution = 1000 mlDensity of the solution = 0.6 g/mlWeight of the solution = V x d = 600 gWeight of solute = Wsolution-Wsolute                          = (600 - 150) g                         = 450 gmolality (m) = nsolute×1000Wsolvent                   =1.5×1000450=3.33 m
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