First slide

Concentration methods

Question

Molarity of a solution of density 0.6 g/ml is 1 M. Molality of the same solution under similar conditions will be (Molar mass of solute - 150 g)

Moderate

A

4.59 m
B

2.22 m
C

1.89 m
D

3.33 m

Solution

Molarity of the solution = 1 M
Number of moles of solute = 1
Volume of the solution = 1000 ml
Density of the solution = 0.6 g/ml
Weight of the solution = V x d = 600 g
Weight of solute = $W_{solution} - W_{solute}$
= (600 - 150) g
= 450 g
molality (m) = $n_{solute} \times \frac{1000}{W_{solvent}}$
= $1 \times \frac{1000}{450} = 2.22 m$

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