The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl and 250 mL of 2 M HCl will be

Amount of HCl in the resultant solution is n=M1V1+M2V2=0.5M750×10−3L+2M250×10−3L=875×10−3moln=M1V1+M2V2=0.5M750×10−3L+2M250×10−3L=875×10−3molTotal volume of the resultant solution is V=V1+V2=750+250×10−3L=1LMolarity of the resultant solution is M=nV=875×10−3mol1L=0.875 mol L−1=0.875 M