1 mole CaCO3(s) is heated in 5.6 lit vessel so that equilibrium is established at 1092 K . If KP for CaCO3(S)⇌CaO(S)+ CO2(g) at this temperature is 4 atm, equilibrium concentration of CO2 (in mol-lit−1 )

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

111.2

133.6

122.4

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

KP=4 atm=PCO2 P V=n R T P=nV R T P=[CO2] R T 4=[CO2]×22.4273×1092 [CO2]=122.4M .

Watch 3-min video & get full concept clarity