Q.
0.4 mole of CO taken in a 2 L flask is maintained along with a catalyst at 812 K so that the reaction : CO(g) + 2H2(g) ⇌ CH3OH(g) can takes place , H2 is introduced until total pressure of system is 20 atm & 0.2 moles of CH3OH is formed at equilibrium then the correct statements among the following:
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a
Kc of reaction is 100 M-2
b
Kp of reaction is 0.022 atm-2
c
In absence of catalyst final pressure is 33.3 atm
d
Total number of moles in absence of catalyst is 0.5
answer is A.
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Detailed Solution
T = 812 K ,P = 20 atm , V = 2 Lit.CO(g) + 2H2(g) → CH3OH(g) 0.4 – x a- 2x x = 0.2 mol PV = nRT a = 0.6 Kc = 100 Kp=Kc (RT)Δn, In absence of catalyst CH3OH formation is negligible. Then total no.of mole = nCO + nH2 = 1
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