2 mole each of A and B are allowed to react to attain the following equilibrium in a 1L vessel 2Ag + Bg⇌A2Bg . At equilibrium 0.5 mole of A2B is formed. The value of Kc for the decomposition of A2B is
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a
13 lit2mole2
b
1 molelit
c
3 mole2lit2
d
2 molelit
answer is C.
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Detailed Solution
2A + B⇌ A2B Δn=1-3=-2 2 2 0 2 – 2x 2 – x x [as x = 0.5] 1 1.5 0.5 Kc=0.512×1.5=13lit2mole-2 ∴ Kc(Reverse)=3 mole2/lit2