2 mole each of A and B are allowed to react to attain the following equilibrium in a 1L vessel 2Ag + Bg⇌A2Bg . At equilibrium 0.5 mole of A2B is formed. The value of Kc for the decomposition of A2B is

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13 lit2mole2

1 molelit

3 mole2lit2

2 molelit

answer is C.

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Detailed Solution

2A + B⇌ A2B Δn=1-3=-2 2 2 0 2 – 2x 2 – x x [as x = 0.5] 1 1.5 0.5 Kc=0.512×1.5=13lit2mole-2 ∴ Kc(Reverse)=3 mole2/lit2

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