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Q.

2 mole each of A and B are allowed to react to attain the following equilibrium in a 1L vessel 2Ag + Bg⇌A2Bg .  At equilibrium 0.5 mole of A2B is formed.  The value of Kc for the decomposition of A2B is

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a

13 lit2mole2

b

1 molelit

c

3 mole2lit2

d

2 molelit

answer is C.

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Detailed Solution

2A   +   B⇌      A2B       Δn=1-3=-2 2             2            0 2 – 2x    2 – x      x [as x = 0.5] 1             1.5         0.5 Kc=0.512×1.5=13lit2mole-2 ∴  Kc(Reverse)=3  mole2/lit2
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