1, mole each of CaC2, AI4C3, Mg2C3 reacts with H2O in separate open flask. Numerical value of work done by the system is in order

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CaC2 < Al4C3 : Mg2C3

CaC2 < Al4C3 < Mg2C3

CaC2 = Mg2C3 < Al4C3

CaC2 = Mg2C3 = Al4C3

answer is C.

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Detailed Solution

CaC2(s)1 mol+2H2O⟶Ca(OH)2+C2H21 mol(g)Al4C3(s)+12H2O⟶4Al(OH)3+3CH43 mol(g)Mg2C31mol(s)+4H2O⟶2Mg(OH)2+C3H41mol(g)Thus, CaC2 = Mg2C3 < Al4C3.

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