2 mole, equimolar mixture of Na2C2O4 and H2C2O4 required V1L of 0.1 M KMnO4 in acidic medium for complete oxidation. The same amount of the mixture required V2L of 0.2 M NaOH for neutralization. The ratio of V1 to V2 is:

2 mole, equimolar mixture of Na2​C2O4 and H2C2O4​ required V1​L of 0.1M KMnO4 in acidic medium.As the mixture is equimolar, 1 mole of each, Na2​C2O4 and H2​C2O4​ are present.eq. of Na2C2O4+eq.of H2C2O4  = eq. of KMnO41x2+1x2= V1x0.1x5 ; (∵n-factor of KMnO4=5 , n-factor of Na2C2O4=n-factor of H2C2O4=2)  V1=8Leq.of H2C2O4= eq.of NaOH1x2 =0.2 x V2; V2=10LHence, V1:V2=8:10=4:5