Mole fraction of ethanol in ethanol water mixture is 0.25. Hence, the percentage concentration of ethanol by weight of mixture is

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25%

75%

46%

54%

answer is C.

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Detailed Solution

χ2=n2n1+n2=0.25 (ethanol) solute) Mw2=46 gχ1=n1n1+n2=0.75 (water) (solvent) Mw1=18gχ1χ2=n1n2=31⇒W1×Mw2Mw1×W2=31W1×4618×W2=3W1W2=1.17∴W2W1+W2=0.46

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