Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The mole fraction of glucose C6H12O6 in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is ___________.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

answer is 47.00.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

m. f. of glucose =moles   of   glucosemoles   of  glucose+moles  of  H2O0.1=110=11+9So glucose moles = 1, (h glucose)        hH2O=9 W glucose =1×180grm           WH2O=9×18 grmas  Mass % of H2O=ωH2O×100ωH2O+ωglucose=9×18×100(9×18)+180  =162×100342=47.368
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring