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Q.

The mole fraction of a solute in solution is 0.1. A t 298 K, molarity of this solution is the same as its molality. Density of this solution at 298 K is 2.0 g cm−3.The ratio of the molecular weight of the solute and solvent, MWsoluteMWsolvent , is

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answer is 9.

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Detailed Solution

XB=0.1=nBnA+nBnB=0.1,nA=0.9m=M⇒1000ml⇒2000g⇒1000g of solute +1000g of solvent XB=0.1=1000MB1000MA+1000MB⇒100MA+100MB=1000MB⇒1MA+1MB=10MB⇒1MA=9MB⇒MBMA=9

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