The mole fraction of urea in an aqueous urea solution containing 900g of water is 0.05. If the density of the solution is 1.2g cm-3, the molarity of urea solution is ___(Given data: Molar masses of urea and water are 60g mol-1 and 18g mol-1, respectively)

Xurea= 0.05            Mass of water = 900 gmNumber of moles of water = nH2O=90018=50 Let moles of urea = nunUnU+50=0.05nU=5019 Mass of urea =5019×60 Given density (d) of solution =1.2g/ml . Vsohtion = mass of solution  density (g/cc)=900+50×60191.2M=nUVml×1000=5019900+50×6019×10001.2=2.98