Mole fraction of water vapour in moist air is 0.05. If the total pressure of moist air is 1.8 atm then the partial pressure of dry air will be

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Detailed Solution

pwatervapour = Ptotal×Xwatervapour = 1.8(0.05)atm = 0.09atm Pdryair = Ptotal−Pwatervapour =1.8−0.09 = 1.71atm

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