Mole fraction of water vapour in the water saturated air is 0.02. If total pressure is 1 .2 atm, partial pressure of dry air is

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1.18 arm

1.22 atm

1.176 arm

1.224 atm

answer is C.

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Detailed Solution

χ( dry air )=1−0.02=0.98atm ∴ Partial pressure (dry air) =0.98×1.2=1.176

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