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Q.

For 0.2 mole of a gas, the van der Waals' equation can be written as

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a

P+0.2aV2V-0.2b=0.2 RT

b

P-0.2aV2V+0.2b=0.2 RT

c

P+0.04aV2V-0.2b=0.2 RT

d

P-0.04aV2V-0.04 b=0.04 RT

answer is C.

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Detailed Solution

Put n = 0.2 in van der Waals' equation P+an2V2V-nb=nRT
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