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Q.

A mole of N2H4 loses 10 mol of electrons to form a new compound γ Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in γ (There is no change in the oxidation number of hydrogen.)

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a

-1

b

-3

c

+3

d

+5

answer is C.

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Detailed Solution

N2H4⟶2y+10e− 2x =-4 in hydrazine it looses 10 moles of electrons i.e from -4 to +6 therefore two nitrogens in product will have charge +6 hence each nitrogen will be +3

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