0.1 Mole of N2O4(g) was sealed in a tube under one atmospheric conditions at 25oC. Calculate the number of moles of NO2(g) present, if the equilibrium N2O4(g)⇌2NO2(g)Kp=0.14 is reached after some time :

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1.8×102

2.8×102

0.036

2.8×10−2

answer is C.

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Detailed Solution

N2O4(g)⇌2NO2(g) t=0; 0 1 mole 0 t=eq. (0.1-x) 2x kp=PNO22PN2O41 0.14=2x0.1+x×120.1-x0.1+x×11 x=0.0184 nNO2=0.036

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