2 mole nitrogen and 6 mole hydrogen are mixed and heated in 10 lit vessel. If 1.5 mole of nitrogen is present in the equilibrium mixture, amount of ammonia in the mixture will be

N2+3H2⇌2NH3             2           6                 0             x           3x              2x_      (2−x)    (6−3x)      2x              Given 2−x=1.5                ⇒x=2−1.5=0.5               [NH3]=2x=2×0.5 =1 mole                 WNH3=1×17 = 17 gr