2.0 mole of PCl5 were introduced in a vessel of 5.0 L capacity of a particular temperature. At equilibrium, PCl5 was found to be 35% dissociated into PCl3 and Cl2 The value of Kc for the reaction PCl3(g)+Cl2(g)⇌PCl5(g)

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0.075

0.377

1.33

13.3

answer is A.

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Detailed Solution

PCl5 ⇌ PCl3+Cl2 t=0; 0.4M 0 0 teq.; (0.4-x) x x x=35100(0.4)=0.14 Now kc=PCl3Cl2PCl5=0.14×0.140.4-0.14=0.075

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