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Q.

2.0 mole of PCl5 were introduced in a vessel of 5.0 L capacity of a particular temperature. At equilibrium,  PCl5 was found to be 35% dissociated into PCl3 and Cl2 The value of Kc for the reaction  PCl3(g)+Cl2(g)⇌PCl5(g)

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a

0.075

b

0.377

c

1.33

d

13.3

answer is A.

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Detailed Solution

PCl5 ⇌ PCl3+Cl2 t=0;  0.4M        0       0 teq.;  (0.4-x)      x       x x=35100(0.4)=0.14  Now kc=PCl3Cl2PCl5=0.14×0.140.4-0.14=0.075
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