First slide

Work

Question

2 mole of zinc is dissolved in HCI at 25^o'C. The work done in open vessel is

Easy

A

-2.477 KJ
B

-4.955 kJ
C

0.0489 KJ
D

None

Solution

$\begin{array}{l} w = - P \cdot ΔV = - n_{H_{2}} \cdot RT \\ = - \frac{2 \times 8 .314 \times 298}{1000} = - 4 .955 kJ \end{array}$

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