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Q.

2 mole of zinc is dissolved in HCI at 25o'C. The work done in open vessel is

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a

-2.477 KJ

b

-4.955 kJ

c

0.0489 KJ

d

None

answer is B.

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Detailed Solution

w=−P⋅ΔV=−nH2⋅RT=−2×8.314×2981000=−4.955kJ
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