Molecular orbital electronic configuration for ‘X ’ anion isKK(σ2s)2(a2s)2π2px2π2py2a2pz2π2px∗The anion ‘X ’ is

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N2−

O2−

N22−

O22−

answer is A.

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Detailed Solution

Given electronic configuration of anion X is ∴ Total number of electrons of anion X = 15Hence, the anion X is N2-.

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