Q.

Molecular orbital theory is based on the principle of linear combination of atomic orbitals (LCAO). According to LCAO, when respective atomic orbitals of the atoms interact, they undergo constructive interference as well as destructive interference giving two type of molecular orbitals, i.e., bonding molecular orbital and antibonding molecular orbital of electrons. Electrons in these orbitals are filled according to aufbau principle, Pauli's exclusion principle and Hund rule.Which of the following is INCORRECT?Which of the following pairs have identical bond order?  Among the following the INCORRECT statement

Moderate

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a

During N2+ formation, one electron is removed from the bonding molecular orbital.

b

During O2+ formation, one electron is removed from the antibonding molecular orbital

c

During O2− formation, one electron is added to the bonding molecular orbital.

d

During CN- formation one electron is added to the bonding molecular orbital

e

N2+and NO

f

F2 and Ne2

g

O2 and N2

h

C2 and N2

i

NO has one unpaired electron in the antibonding molecular orbital

j

bond length of NO> NO+

k

magnetic moment of N2+is 3 B.M.

l

magnetic moment of O2 is zero

answer is , , .

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Detailed Solution

(1) N2+⇒σ1s2,σ˙1s2,σ2s2,σ˙2s2,πpx2=π2p22,σ2pz1 (2) O2+⇒σ1s2,σ˙1s2,σ2s2,σ˙2s2,σ2px2,π2πy2=π2π22,π2πy1=π2πz (3) O2−⇒σ1s2,σ˙1s2,σ2s2,σ˙2s2,σ2px2,π2py2=π2p22,π˙2py2=π˙2p21 (4) CN−⇒σ1s2,σ˙1s2,σ2s2,σ˙2s2,π2py2=π2p22,σ2px2Electron is added to anti bondingBoth have same bond order of 2.5. Flourine has 1,Nitrogen has 3, oxygen has 2.
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