First slide
Chemical reactions and calculations
Question

The Molecular weight of a oxide of an element is 44. The Equivalent weight of the element  is 14. The atomic weight of the element is

Moderate
Solution

Let the formula of oxide = M20x = 44

2×M+x×16=442(E×x)+x×16=442(14×x)+16x=44

x=1

Atomic weight = 14 × 1 = 14

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