First slide

Chemical reactions and calculations

Question

The Molecular weight of a oxide of an element is 44. The Equivalent weight of the element is 14. The atomic weight of the element is

Moderate

A

14
B

28
C

42
D

56

Solution

Let the formula of oxide = M₂0_x = 44
$\begin{array}{l} 2 \times M + x \times 16 = 44 \\ 2 (E \times x) + x \times 16 = 44 \\ 2 (14 \times x) + 16 x = 44 \end{array}$
$∴ x = 1$
Atomic weight = 14 × 1 = 14

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