The Molecular weight of a oxide of an element is 44. The Equivalent weight of the element is 14. The atomic weight of the element is

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answer is A.

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Detailed Solution

Let the formula of oxide = M20x = 442×M+x×16=442(E×x)+x×16=442(14×x)+16x=44∴x=1Atomic weight = 14 × 1 = 14

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