The molecular weights of two ideal gases A and B are respectively 100 and 200. One gram of A occupies V litres of volume at STP. What is the volume (in litres) occupied by one gram of B at STP ?
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a
V/2
b
V
c
V2
d
2V
answer is A.
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Detailed Solution
V∝wM(p,T are constant )VB=VAMAwBwAMB=V×100×11×200=V2