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a
Pyramidal and more basic than (CH3)3N
b
Planar and less basic than (CH3)3N
c
Pyramidal and less basic than (CH3)3N
d
Planar and more basic than (CH3)3N
answer is B.
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Detailed Solution
Due to availability of empty d-orbitals in the valency shell of "Si" the lone [pair electron which are available on nitrogen involves in π bond (dative bond ) formation with the empty d-orbitals.In SiH33N the "N" undergoes sp2 hybridisation and attains trigonal planority.Due to the involvement of lone pair on nitrogen in the pi bond formation ,hence the availability of electron pair for H+ ion ↓es & Hence basic nature ↓es