Q.

The molecule (SiH3)3N is

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a

Pyramidal and more basic than (CH3)3N

b

Planar and less basic than (CH3)3N

c

Pyramidal and less basic than (CH3)3N

d

Planar and more basic than (CH3)3N

answer is B.

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Detailed Solution

Due to availability of empty d-orbitals in the valency shell of "Si" the lone [pair electron which are available on nitrogen involves in π bond (dative bond ) formation with the empty d-orbitals.In SiH33N the "N" undergoes sp2 hybridisation and attains trigonal planority.Due to the involvement of lone pair on nitrogen in the pi bond formation ,hence the availability of electron pair  for H+ ion ↓es & Hence basic nature ↓es
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