Q.

The molecule with pentagonal bipyramidal geometry is

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a

IF7

b

XeF6

c

XeF2

d

XeF4

answer is A.

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Detailed Solution

Number of electron pairs(EP)=V+M-C+A2; V=Group number of central atom; M=-H, -X, -OH....monovalent groups attached to central atom ; C=Charge of cation ; A=Charge of anion ; V=7,8 respectively for 17th, 18th group elements ; Number bond pairs, BP(according to VSEPR theory)=Number of atoms directly attached to central atom;                                                                                 =7,6 respectively in IF7, XeF6 ; Number lone pairs on central atom(LP)=EP-BP ;                                                          =0,1 respectively in  IF7, XeF6 ; IF7-'7' bp +'0' lp on central atom; sp3d3-Pentagonal bipyramidal; 21 lone pairs/molecule XeF6-'6' bp +'1' lp on central atom ; sp3d3-Distorted octahedral ; 19 lone pairs/molecule Note; Each bonded halogen atom has '3' lone pairs on it ; Orientation of electron pairs is Pentagonal bipyramidal in both the molecules ;
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