1021 molecules are removed from 200 mg of CO2. The moles of CO2 left is
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a
2.88 x 10-3
b
28.8 x 10-3
c
288 x 10-3
d
28.8 x 103
answer is A.
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Detailed Solution
1021 molecules =1021 molecule 6.022×1023 molecule /mol=1.66x10−3 mol 200 mg of CO2=200×10−3g44g/mol=4.54×10−3mol.The number of moles of CO2 remaining = (4.54 -1.66) x 10-3 = 2.88 x 10-3.