Q.

The molecules present in 5.6 L of sulphur dioxide at STP is

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a

1.5×1023

b

1.5×10−23

c

4×1023

d

0.15×1023

answer is A.

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Detailed Solution

22.4L SO2 at N.T.P.                    =6.023×1023 molecules; 5.6LSO2=6.023×1023×5.6/22.4=1.5×1023 molecules.
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