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Q.

11 moles of  FeSO4 are treated with one mole of acidic  KMnO4 solution and resulting solution is further treated with acidic  K2Cr2O7 solution. As a result, remaining FeSO4 is completely oxidised. Find out minimum number of moles of  K2Cr2O7 present in the solution.

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a

2

b

4

c

6

d

1

answer is D.

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Detailed Solution

Fe2++KMnO4⟶H+Mn2++Fe3+11 moles            1 mole(excess reagent)  (Limiting reagent)nFe2+( reacted )×1=nKMnO4×5mole⇒nFe2+( reacted )=1×5=5mole So, nFe2+( left )=11−5=6moleNow, reaction with acidic  K2Cr2O7Cr2O72−+Fe2+⟶H+Cr3++Fe3+x mole  6mole⇒x×6=6×1∴x=1
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