15 moles of H2 and 5.2 moles of I2 are mixed and allowed to attain equilibrium at 5000C. At equilibrium, the concentration of HI is found to be 10 moles. The equilibrium constant for the formation of HI is

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Detailed Solution

H2 + I2 ⇌ 2HI15 5.2 0(15 - 5) (5.2 - 5) 10KC=HI2H2 I2 = 10 × 1010 × 0.2=50

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