First slide

PH of strong acids and strong bases

Question

0.1 moles of HCl is dissolved in hundred litre solution. At 298 K, $p^{H}$ of the solution is

Easy

A

2
B

3
C

1.6990
D

1.3010

Solution

$N_{a} = [H^{+}] = 0.1 \times \frac{1}{100} = 10^{- 3} N; p^{H} = - \log 10^{- 3} = 3;$

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